// Rpw Rduction Algorythm.cpp : Defines
// the entry point for the console applicat
// ion.
//solves a linear system whith a ordered
// pair solution
#include "stdafx.h"
#include "iostream.h"
int intboolfalsetrue
enum CHOICE {again = 1,no};
int main(int argc, char* argv[])
{
cout << "****** Produced by Daniel G. From Alaska ******\n";
cout << "****** Use it. Charish it. Speed up your Homework.\n\n";
int choice; //input for loop
int fQuit = false; //setup for loop
// create, input values
double aOne, aTwo, aThree, bOne, bTwo, bThree,Y,X; //variables
while(!fQuit)
{
//input information
cout << "Enter a(1), a(2), and a(3) from the equation a(1)x+a(2)y=a(3)\n";
cout << "a(1): ";
cin >> aOne;
cout << "a(2): ";
cin >> aTwo;
cout << "a(3): ";
cin >> aThree;
cout << "\nEnter b(1), b(2), and b(3) from the equation b(1)x+b(2)y=b(3)\n";
cout << "b(1): ";
cin >> bOne;
cout << "b(2): ";
cin >> bTwo;
cout << "b(3): ";
cin >> bThree;
//check for non odered pair system
if (aOne==0)
{
cout << "Invalid entry for a(1): Cannot be 0\n";
goto end;
}
//Row-Reduction-Algorythm procedure
aTwo = aTwo/aOne;
aThree = aThree/aOne;
bTwo = bTwo + ( -1 * aTwo * bOne);
bThree= bThree + (-1 * aThree * bOne);
if (bTwo ==0)
{
cout << "Answer not a single ordered pair.\n";
goto end;
}
Y=bThree / bTwo;
X= aThree - (aTwo * Y);
cout << "Solution: (" < end: cout << "\nRepeat? (1) yes (2) no\n"; cin >> choice; switch (choice) { case again: break; case no: fQuit = true; break; default: cout << "Invalid."; fQuit = true; break; } } return 0; }